Water Supply Engineering Solved Problems Pdf [UPDATED]

Growth rates: r1 = (55-45)/45 = 0.2222 (22.22%) r2 = (68-55)/55 = 0.2364 r3 = (84-68)/68 = 0.2353 Average r = 0.2313 (23.13%) P2030 = 84,000 × (1+0.2313)² = 84,000 × 1.515 = 127,260

Make a mass diagram (cumulative supply – cumulative demand): water supply engineering solved problems pdf

Q_peak hourly = 2.7 × 15,000 = 40,500 m³/day (468.75 L/s) Growth rates: r1 = (55-45)/45 = 0

h_f = 10.67 × L × Q^1.852 / (C^1.852 × D^4.87) D = 0.4 m, Q = 0.25 m³/s h_f = 10.67 × 800 × (0.25^1.852) / (120^1.852 × 0.4^4.87) 0.25^1.852 = 0.065, 120^1.852 = 7061, 0.4^4.87 = 0.4^4 × 0.4^0.87 = 0.0256 × 0.459 = 0.01175 h_f = (10.67×800×0.065) / (7061×0.01175) = 555 / 83.0 = 6.69 m 4. Problem Set 4: Pump Sizing Problem 4.1 A pump delivers water from a lower reservoir (EL 50.0 m) to an elevated tank (EL 95.0 m). Discharge = 50 L/s. Pipe diameter = 200 mm, length = 1200 m, f = 0.02. Calculate: (a) Total dynamic head (b) Hydraulic power required (c) Brake horsepower if pump efficiency = 75% Pipe diameter = 200 mm, length = 1200 m, f = 0

Q_avg = 75,000 × 200 = 15,000,000 L/day = 15,000 m³/day (173.6 L/s)

Hydraulic power P_h = ρ × g × Q × H = 1000 × 9.81 × 0.05 × 60.46 = 1000 × 9.81 × 3.023 = 29,660 W = 29.66 kW